easy

easyではわざわざ1ページを作るほどでもないシンプルな問題や簡単な問題を解く．

Archived Challenges - July 2021 smth here

:4E7L6oD*049p==b?8b=D07EHN

色々試すとROT47だとわかる． ictf{e@sY_chAll3ng3ls_ftw}

Archived Challenges - August 2021 I can't hear you!

100011110010101100010101001011011100100010111110100011101101000110010010100101110010001110011100100110011101011100101110010110010100011001010110100101010011011011011111001110011100001000011110100101110100001010100111100101011010101011011100001101001011101101110011100011110001011010010100010101110010000110000011010110110001100000100111100011101110100100101100001110010011101110110101010110011001010101001100001011101010100101100111001111101101010001011101001101101011010010010001100110011010110001010101010101011011100111100010100101111100010111001101010011010110011011011111100110101110010101010010001101101100110000001000010011110100010111001101010110010101011101111011000111011001110111111001010110110010011011011110001011101100101010001110001101011111100010101110010111110100001011001011100011110011101011001110

repetition codeというものが存在する．

from Crypto.Util.number import *
s = (omit)
t = ""

for i in range(0,len(s),3):
    a = int(s[i:i+3],2)
    if a == 0 or a==1 or a==2 or a==4:
        t += "0"
    else:
        t += "1"


n = int(t,2)
print(long_to_bytes(n))